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STPCPY (3) | C library functions | Unix Manual Pages | :man

NAME

stpcpy - copy a string returning a pointer to its end

CONTENTS

Synopsis
Description
Example

SYNOPSIS



#include <string.h>



"char *stpcpy(char *"dest", const char *"src);

DESCRIPTION

The stpcpy() function copies the string pointed to by src (including the terminating ‘\0’ character) to the array pointed to by dest. The strings may not overlap, and the destination string dest must be large enough to receive the copy.

"RETURN VALUE"

stpcpy() returns a pointer to the end of the string dest (that is, the address of the terminating null character) rather than the beginning.

EXAMPLE

For example, this program uses stpcpy to concatenate foo and bar to produce foobar, which it then prints.


#include <string.h>


int
main (void)
{
char *to = buffer;
to = stpcpy (to, "foo");
to = stpcpy (to, "bar");
printf ("%s\n", buffer);
}

"CONFORMING TO"

This function is not part of the ANSI or POSIX standards, and is not customary on Unix systems, but is not a GNU invention either. Perhaps it comes from MS-DOS.

"SEE ALSO"

strcpy(3), bcopy(3), memccpy(3), memcpy(3), memmove(3)


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